cross produced the following oflsprings: Ddee (12), ddlee (350) DdEe (250), DDee
ID: 207077 • Letter: C
Question
cross produced the following oflsprings: Ddee (12), ddlee (350) DdEe (250), DDee(1000) I n a dihybrid test cross are unlinked and follow Mendel's laws. The 30. Based on the infomation given, state the hypothesis (your hypothesis should state Mendel's laws, the typeof os, 31. Vhat is the ratio for a trihybrid test cross Gircde the coret answe 32. What is the total number of offspring- 33. Identify the degrees of freedom equation. Circle the correct answer 34. How many different phenotypes are produced in the offsprings? 35. What are the degrees of freedom for the problem above? C. 1:1:1:1:1:1 D, 1:1:1:1:1:1:1 E. None of the answers is correct A. n+1 B, n-1 D' (a+b)^ = 1 li Puncedernd- Table of X Values df P 0.99 0.95 0.80 0.50 0.20 0.05 0.01 0,00157 0,00393 | 00642 0.455 0.103 0.46 1386319 991 9.210 1005 2x6 4642 7815 11345 1649 3.357 98 9488 13.277 1.145 243 375 11.070 1508 1.635 3070348s58 12592 16.812 2167 382263.014067 18415 2733 | 4.594 | 7.344 | 11.030 | 15507 20000 3.325 5.330 8343 12242 6 2166 3,040 6.179 | 9.342 | 13.442 | 18.307 23209 10307 :4339 | 19.311 | 24.996 | 30.578 10851 14578 19.337 25038 31.410 37.566 14011 | 18.940 | 24337 | 30.675 | 37.652 44.314 18.493 | 29.336 | 36.250 43,773 1 50,892 40297 5 0.554 6 Q872 7 1.239 8164 9 2088 0 2558 15 5.222 7251 8250 2S 11524 0 14.953 36. Identify the Chi square analysis equation. Circle the correct answer A n+1 B n-1 x! (n-x)yExplanation / Answer
30. dihybrid test cross according to mendel laws produce a ratio of 1:1:1:1
So the hypothesis will be according to mendel law dihybrid test cross ratio will be 1:1:1:1
however the data given are far away from test cross ratio so null hypothesis might be rejected but it m=needs more calculations to confiem rejection.
31. E trihybrid test cross ratio is 1:1:1:1:1:1:1:1
32. in dihybrid cross total no. of offsrpins are 16 and in trihybrid cross it is 64
33. degree of freedom is n-1 answer is B
34. In dihybrid cross 4 phenotypes are produced and in trihybrid cross 8 phenotypes are produced
35. degree of freedom = no. of phenotypes-1
so 4-1=3
36. answer is C Chi square= summation of (O-E)2/E
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