The photoelectric effect experiment is often carried out by using a mercury ligh

Question

The photoelectric effect experiment is often carried out by using a mercury light source to illuminate a particular surface. The emission spectrum of mercury has strong lines at wavelengths of 365.5 nm (ultraviolet), 404.7 nm (violet), 435.8 nm (blue), and 546.1 nm (green). The light can be passed through a diffraction grating to separate the light into these different wavelengths.

If the maximum kinetic energy of the emitted electrons is 1.13 eV when the green light illuminates the surface, what will the maximum kinetic energy of the emitted electrons be when the blue light illuminates the surface?

Explanation / Answer

Egreen = hc/ = 4.136e-15*3e8/546.1e-9 = 2.27211 eV

= Egreen - K = 2.27211 - 1.13 = 1.14211 eV

Eblue = hc/ = 4.136e-15*3e8/435.8e-9 = 2.84718 eV

K = Eblue - = 2.84718 - 1.14211 = 1.705 eV

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.