This is what we came up with but still got it wrong.... First find the impedance

Question

This is what we came up with but still got it wrong....

First find the impedance of the circuit.

The impedance is given by:

Where:

R is the resistance

For your problem:

f = 1.25 kHz = 1250 Hz

L = 23 mH = 23x10-3H

C = 150 nF = 150x10-9F

Hence:

The current in the circuit is thus:

Capacitors and Inductors do not absorb nor

dissipate average power. All average power

delivered by the source is absorbed the resistor.

Hence both answers will be the same.

The power dissipated in the resistor is:

The power delivered by the AC generator is:

Explanation / Answer

f=1250 Hz==>L=23 mH==>C=150 nF==>R=385

XL=2**1250*0.023=180.6 ==>XC=1/(2**1250*150E-9)=849

Z=(R2+(XL-XC)2)771 =Req

120 V/771 0.15561 A=Itotal==>I2*R=0.155612*77118.67 W

I2*R=0.155612*3859.32 W

Part A) 18.67 W average power only at steady state

Part B) 9.32 W

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