Lithium, beryllium, and mercury have work functions of 2.30 eV, 3.90 eV, and 4.5

Question

Lithium, beryllium, and mercury have work functions of 2.30 eV, 3.90 eV, and 4.50 eV, respectively. If 267 nm light is incident on each of these metals, determine the following.
(a) which metals exhibit the photoelectric effect...pick one of following...
-none
-lithium only
-lithium and beryllium
-mercury only
-mercury and beryllium
-all three


(b) the maximum kinetic energy of the photoelectrons in each case (Enter 0 if not applicable.)


Lithium =______________eV

Beryllium=_____________eV

Mercury =_____________eV

Explanation / Answer

=267nm

E=4.64 eV

so all three will emit electrons as E>work function for all three

(b)

lithium=4.64-2.3=2.34eV

beryllium=4.64-3.9=0.74 eV

mercury=4.64-4.5=0.14eV

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