I already know the answers to the problem below: a)= 849 N b) = 1.88 m/s Please

Question

I already know the answers to the problem below: a)= 849 N b) = 1.88 m/s

Please show all your work how you derived to the answers.

Two boats pull a 75.0-kg water skier, as illustrated in the figure below. (a) If each boat pulls with a force of 600 N and the skier travels at a constant velocity, what is the magnitude of the retarding force between the water and the skis? (b) Assuming that the retarding force remains constant, if each boat pulls with a force with a force of 700 N, what is the magnitude of the acceleration of the skier?

Explanation / Answer

Part of the force of each boat pulls the skier forward and part cancels out a componenet from the other boat. Top boat right = 600N cos 45 Bottom boat right = 600N cos 45 total force to the right = 2F cos 45 = 2*600N*SQRT(2)/2 = 600N SQRT(2) = 600*1.414N The skier would accelerate were there a net force, so the friction force is equal to the force to the right = 848.53N = retarding force (B) Now we increase the force from the boats and keep the retarding force at 848.53N total force to the right = 2F cos 45 = 700NSQRT(2) = 990N net force is 141.42N. F = ma a = F/m = 141.42N/75.0kg = 1.88 m/s^2

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.