RLC circuit: R= 2.80 C= 36.4 nF L= 57.0 nH E(t)= 12.5 sin [2(3.80 MHz)t] a) Dete
ID: 2066163 • Letter: R
Question
RLC circuit: R= 2.80 C= 36.4 nF L= 57.0 nH E(t)= 12.5 sin [2(3.80 MHz)t]
a) Determine the reactance of the capacitor in the circuit
the answer is 1.15
what is the formula used to calculating the answer?
b) Determine the impedance
the answer is 2.81
what is the formula used in calculating the answer?
c) determine the phase angle to complete the following statement:
The current in the circuit is given by i(t)=Imax sin[2(3.80MHz)t-]
the answer is 4.29 degrees
what is the formula used to calculate the phase angle?
d) For the conditions given, is the current: in phase with, leading, or lagging the voltage?
the anser is, it is lagging
why?
Explanation / Answer
a)
E(t)= 12.5 sin [2(3.80 MHz)t]
>>>> = 2(3.80*10^6) = 2*3.14*3.80*10^6 = 23.864 * 10^6 rad/s
XC = 1/(C) = 1/(23.864e6 * 36.4e-9) = 1.15 ohm
b)
XL = L * = 57e-9 * 23.864e6 = 1.36 ohm
Z = (R2 + (XL - XC)2) = 2.81 ohm
c)
Z = R + j(XL - XC)
>>>> = tan-1 ((XL - XC)/R) = 4.29 degrees
(Notr that i(t)=V(t)/Z = Imax sin[2(3.80MHz)t-])
d)
because =+4.29 is positive
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