The volume of air space in the passenger compartment of a 3720 kg car is 4.90 m3
ID: 2066090 • Letter: T
Question
The volume of air space in the passenger compartment of a 3720 kg car is 4.90 m3. The volume of the motor and front wheels is 0.736 m3, and the volume of the rear wheels, gas tank, and trunk is 0.827 m3; water cannot enter these two regions. The car rolls into a lake. (a) At first, no water enters the passenger compartment. How much of the car, in cubic meters, is below the water surface with the car floating (Fig. 14-43)? (b) As water slowly enters, the car sinks. How many cubic meters of water are in the car as it disappears below the water surface? (The car, with a heavy load in the trunk, remains horizontal.)
The volume of air space in the passenger compartment of a 3720 kg car is 4.90 m3. The volume of the motor and front wheels is 0.736 m3, and the volume of the rear wheels, gas tank, and trunk is 0.827 m3; water cannot enter these two regions. The car rolls into a lake. (a) At first, no water enters the passenger compartment. How much of the car, in cubic meters, is below the water surface with the car floating (Fig. 14-43)? (b) As water slowly enters, the car sinks. How many cubic meters of water are in the car as it disappears below the water surface? (The car, with a heavy load in the trunk, remains horizontal.)Explanation / Answer
(a) in order to float the car needs to displace 3720kg of water. That means that the volume of the car below the water will be equal to the volume of the displaced water (3720kg). The density of the water is 1000 kg/m^3, then the volume of the car below the water will be 3.72 m^3 (b) water cannot penetrate motor ans wheels, which is 0.736+0.827=1.563 m^3 passenger compartment is 4.9 m^3 The total V of the vehicle is = 4.9+1.563=6.463 m^3 when it is under the surface that means the total volume of water displaced is 6.463 m^3 substruct from it the initial volume need to float 6.463-3.72=2.743 m^3 this is the volume of water that need to penetrate the car.
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