\"Play Bulb!\" The circuit above shows a battery, two identical lightbulbs, an i

Question

"Play Bulb!"

The circuit above shows a battery, two identical lightbulbs, an inductor and a switch. All of the components may be considered to be ideal. Initially, no currents are flowing. At t = 0, the switch is closed, it is left closed for a long time, then it is reopened, and another long time passes.

Just after the switch is first closed, which bulb will be brighter? What about just before it is reopened? Just after it is reopened? Finally, which bulb will emit more total light during the course of the experiment?

Explanation / Answer

see,
just after closing, current in the bulb having the inductor in its circuit=0
so other bulb will be brighter
but when switch is opened,
inductor is the voltage source
and hence it gives equal current to both the bulbs
so both are equally bright
:)

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