A ray of light impinges from ;air onto a block of ice (n = 1.309) at a 60.0 degr

Question

A ray of light impinges from ;air onto a block of ice (n = 1.309) at a 60.0 degree angle of incidence. Assuming that this angle remains the same, find the difference theta2,ice - theta2,water in the angles of refraction when the ice turns to water (n = 1.333). A spotlight on a boat is 2.5 m above the water, and the light strikes the water at a point that is 8.0 m horizontally displaced from the spotlight (sec the drawing). The depth of the water is 4.0 m. Determine the distance d, which locates the point where the light strikes the bottom. The drawing shows a coin resting on the bottom of a beaker filled with an unknown liquid. A ray of light from the coin travels to the surface of the liquid and is refracted as it enters into the air. A person sees the ray as it skims just above the surface of the liquid. How fast is the light traveling in the liquid?

Explanation / Answer

1=tan^-1(8.0 m / 2.5 m) = 73 degree

sin2=(n1/n2)sin1=(1.000/1.333)sin73= 0.72

sin2 = 0.72 so 2 = 46 degree

distance d =

d = 8.0m + 4.0 m tan 46 = 12.1 m

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