Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

A concave mirror has a focal length of 49.0 cm. (a) What is its radius of curvat

ID: 2063276 • Letter: A

Question

A concave mirror has a focal length of 49.0 cm.
(a) What is its radius of curvature?
=_______ cm

(b) Locate the image when the object distance is 100 cm. (Indicate the side of the mirror with the sign of your answer.)
=_______cm

Describe the properties of the image when the object distance is 100 cm. (Select all that apply.)
yes or no.....
real=
virtual=
upright=
inverted=

(c) Locate the image when the object distance is 10.0 cm. (Indicate the side of the mirror with the sign of your answer.)
=_______ cm

Describe the properties of the image when the object distance is 10.0 cm. (Select all that apply.)
yes or no.....
real=
virtual=
upright=
inverted=

Explanation / Answer

Part A)

The radius of curvature of a mirror is twice the focal length

R = 2f = 2(49) = 98 cm

Part B)

The equation here is

1/f = 1/p + 1/q

1/49 = 1/100 + 1/q

q = 96 cm   (positive value means image in front of mirror)

Since q is positive, the image is real. The image will also be inverted and that can be seen by the magnification formula where M = -q/p. The value of the magnification would come out negative indicating the inversion

Part C)

1/f = 1/p +1/q

1/49 = 1/10 + 1/q

q = -12.6 cm (Negative value means image in back of the mirror)

The negative also indicated that the image is virtual. The magnification will come out positive, so the image is upright.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote