A circular loop of conducting wire measuring 12cm in diameter is placed into a .

Question

A circular loop of conducting wire measuring 12cm in diameter is placed into a .60-T magnetic field. What is the magnetic flux through the loop:

a) When the plane of the loop is parallel to the field lines

b) The plane of the loop is rotated until it makes a 60 degree angle with the field lines

c) The plane of loop is rotated until makes a 90 degree angle with the field lines

I know the formula will be Im = B*A*cos(theta); however, I was told that theta for part b) is actually 30 degrees. What is the reason for this? Please answer this question in conjunction with the problem.

Thanks!

Explanation / Answer

As you know = BA cos

for first part

= 90

so = BA = 0

for 2nd part

= 30

so = BA = 0.12 * 0.6*cos 30 = 0.062

for third part

= 0

so = BA = 0.072

Remember that is angle between area vector and field lines and not between the plane of the loop and field lines. So when the plane of the loop made 60 deg. with field lines the are vector which is perpendicular to the plane of the loop made 90-60 = 30 deg.

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