The picture above shows four different cases of a conducting square loop (in ora

Question

The picture above shows four different cases of a conducting square loop (in orange), traveling at speed v and passing through a rectangular region. In the left half of the rectangular region, the magnetic field is uniform and directed into the screen; in the right half, the magnetic field is uniform and directed out of the screen. The field has the same magnitude in each half of the rectangular region, and there is no magnetic field outside the rectangular region.

The square loop measures 20.0 cm by 20.0 cm; the resistance of the loop is 10.0 ohms; the speed of the loop is v = 5.00 m/s; and the magnitude of the magnetic field on each side of the rectangular region is 4.00 T. Calculate the magnitude of the induced current in the loop at the instant shown in case D above.

Thanks

The picture above shows four different cases of a conducting square loop (in orange), traveling at speed v and passing through a rectangular region. In the left half of the rectangular region, the magnetic field is uniform and directed into the screen; in the right half, the magnetic field is uniform and directed out of the screen. The field has the same magnitude in each half of the rectangular region, and there is no magnetic field outside the rectangular region.

Explanation / Answer

Case D:
Induced voltage = -d/dt = -BdA/dt = -2*4*5*0.2 = -8V

Resistance = 10ohm

Current = 8/10 = 0.8 A

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