Two circuits contain an emf produced by a moving metal rod, like that shown in t

Question

Two circuits contain an emf produced by a moving metal rod, like that shown in the drawing. The speed of the rod is the same in each circuit, but the bulb in circuit 1 has one-half the resistance of the bulb in circuit 2. The circuits are otherwise identical. The resistance of the light bulb in circuit 1 is 415 ?, and that in circuit 2 is 830 ?.

http://www.webassign.net/cj8/qu_22_04.gif

(a) Determine the ratio 1/2 of the emfs.
e1/e2=


(b) Determine the ratio I1/I2 of the currents in the circuits.
I1/I2=


(c) If the speed of the rod in circuit 1 were twice that in circuit 2, what would be the ratio P1/P2 of the powers in the circuits?
P1/P2=

Explanation / Answer

E=BLV

(a)

E1=BLV

  E2=BLV

  E1/E2= =1

(b)

V=IR

I1=E1/R1=E1/415

I2=E2/R2=E2/830

  I1/I2= 2

(c)

E1=2BLV

E2=BLV

I1=E1/R1=2BLV/415

I2=E2/R2=BLV/830

P1=E1*I1=2BLV*2BLV/415

  P2=E2*I2=BLV*BLV/830

  P1/P2= 4*830/415

=8

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