Protons are projected with an initial speed vi = 9.96 km/s from a field-free reg

Question

Protons are projected with an initial speed vi = 9.96 km/s from a field-free region through a plane and into a region where a uniform electric field Earrowbold = 720jhatbold N/C is present above the plane as shown in in the figure below. The initial velocity vector of the protons makes an angle with the plane. The protons are to hit a target that lies at a horizontal distance of R = 1.16 mm from the point where the protons cross the plane and enter the electric field. We wish to find the angle at which the protons must pass through the plane to strike the target.

to write an expression for R in terms of vi, E, the charge and mass of the proton, and the angle . (Use the following as necessary: vi, e, E, , and mp for the mass of proton.)
R =

(f) Find the time interval during which the proton is above the plane in the figure above for each of the two possible values of . (Enter your answers from smallest to largest.)

Explanation / Answer

9.96*2/1/2*9.96

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