Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

part 1. B= T part 2. t= s part 3. Find the magnitude of the magnetic field, that

ID: 2059256 • Letter: P

Question

part 1.

B= T

part 2.

t= s

part 3.

Find the magnitude of the magnetic field, that would be needed if the particle were a proton instead of an electron?

B= T

An electron at point B. t= s part 3. Find the magnitude of the magnetic field, that would be needed if the particle were a proton instead of an electron? B= T A to B . B= T part 2. Find the time required for the electron to move from to part 1. Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from . in the figure has a speed of1.46106

Explanation / Answer

Bev=mv²/r ==> B=mv/(er) since Lorentz force = Centripetal force
where
e=charge of the electron = 1.6 *10^-19 cou
m=mass of the electron = 9.1*10^-31 kg
r=0.05 m
v=1.46 *10^6 m/s
B=magnitude of the magnetic field measured in T (teslas)


If the path is a semicircle, then t=T/2=pr/v seconds
= 1.07* 10^-7 s



M=mass of the proton
B=Mv/(er)

mass of proton = 1.67*10-27 kg