*A 40-kg crate is pulled across the ice with a rope. A force of 100 N is applied

Question

*A 40-kg crate is pulled across the ice with a rope. A force of 100 N is applied to the rope at an angle of 30o with the horizontal. Neglecting friction, calculate
the acceleration of the crate. (2.17 m/s/s)
the normal force the ice exerts on the crate as it is pulled. (342 N, up)

Three teenagers push a heavy crate across the floor. Dion pushes with a force of 185 N at 0o. Shirley exerts a force of 165N at 30o, while Joan pushes with a 195 N force at 300o. What is the resultant force on the crate? (434.07 N, 348.520)

Explanation / Answer

For force of ice, you need to find the vertical component of the force, = (sin 30) x 100, = 50N. Then subtract this from (mass x gravity), = 392 - 50, = 342N., and obviously up.

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