A 70.0-kg grindstone is a solid disk 0.550 in diameter. You press an ax down on

Question

A 70.0-kg grindstone is a solid disk 0.550 in diameter. You press an ax down on the rim with a normal force of 160 . The coefficient of kinetic friction between the blade and the stone is 0.60, and there is a constant friction torque of between the axle of the stone and its bearings.
How much force must be applied tangentially at the end of a crank handle 0.500 m long to bring the stone from rest to 120 rev/min in 7.00 ?



Part B
After the grindstone attains an angular speed of 120 rev/min, what tangential force at the end of the handle is needed to maintain a constant angular speed of 120 rev/min?





Part C
How much time does it take the grindstone to come from 120 rev/min to rest if it is acted on by the axle friction alone?

Explanation / Answer

use torque

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