(a) When t = 2.00 s, calculate the magnitude of the force exerted on an electron

Question

(a) When t = 2.00 s, calculate the magnitude of the force exerted on an electron located at point P1, which is at a distance r1 = 4.40 cm from the center of the circular field region.

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(b) When t = 2.00 s, calculate the direction of the force exerted on an electron located at point P1, which is at a distance r1 = 4.40 cm from the center of the circular field region.

(c) At what instant is this force equal to zero?

_________s

Check your answers in units.. for full rating..

Within the green dashed circle shown in the figure below, the magnetic field changes with time according to the expression B = 6.00t3 - 1.00t2 + 0.800, where B is in teslas, t is in seconds, and R = 2.20 cm. (a) When t = 2.00 s, calculate the magnitude of the force exerted on an electron located at point P1, which is at a distance r1 = 4.40 cm from the center of the circular field region. ____________N (b) When t = 2.00 s, calculate the direction of the force exerted on an electron located at point P1, which is at a distance r1 = 4.40 cm from the center of the circular field region. (c) At what instant is this force equal to zero? _________s Check your answers in units.. for full rating..

Explanation / Answer

for P1:

E(2r1) = R2 * (18*t2 - 2*t)

E = (R2/r1) * (9*t2 - t)

   = 0.374

F = qE = 1.6*10-19 * 0.374

   = 0.5984 * 10-19 N

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b) for P2:

E = (r2)*(9*t2 - t)

(we have not r2!!!!)

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c)

9*t2 - t = 0 >>>> t = 0.111 s

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