Runner A is half way through 100 meter race (50 meters to go) and is ahead of ru

Question

Runner A is half way through 100 meter race (50 meters to go) and is ahead of runner B by 2 meters. If both runners have a current speed of 10 m/s. what is the minimum average acceleration of runner B necessary to catch up by the end of the race (assuming that the velocity of runner A remains constant)? Sketch a bowler's arm at the end of the downswing (with the elbow fully extended) with the following vector quantities illustrated on the arm: angular velocity and angular acceleration of the arm linear velocity of the hand centripetal acceleration of the hand tangential acceleration of the hand resultant linear acceleration of the hand

Explanation / Answer

10t = 50 t = 5 sec 52 = 10*5 + 1/2a*25 a = 2*2/25 = 0.16 m/s^2 min acc. = 0.16 m/s^2

Related Questions

Navigate

• Browse (All)
• Browse R
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.