Suppose that block m = .050kg, sometime after reaching the base of the incline,

Question

Suppose that block m = .050kg, sometime after reaching the base of the incline, undergoes a completely inelastic collision with the stationary block M = .075kg. Use the principle of conservation of linear momentum to determine the common speed of the blocks just after the collision. (carry the answer to one decimal place).

V = 3.4 m/s

Suppose that block m = .050kg, sometime after reaching the base of the incline, undergoes a completely inelastic collision with the stationary block M = .075kg. Use the principle of conservation of linear momentum to determine the common speed of the blocks just after the collision. (carry the answer to one decimal place). V = 3.4 m/s

Explanation / Answer

m = .050 kg
M = .075 kg
mv + MV = Vf (m+M)
.05*g sin + .075 * 0 = Vf (.05+.075) 

from here we can get the final velocity .. by knwowing the info about the inclination angle..

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