<p>Two resistors, R1 = 5.5kiloOhms and R2 = 23.0kiloOhms, are connected in paral

Question

<p>Two resistors, R1 = 5.5kiloOhms and R2 = 23.0kiloOhms, are connected in parallel. The parallel pair are connected in series to a third resistor, R3 = 11.0kiloOhms, and a 15.0Volts voltage source to make force a circuit. Find the voltage across and current through each resistor. (Hint: try to solve them in the order given below.) <br />I₃ = &#160; &#160; &#160; &#160; mA <br />V₃ = &#160; &#160; &#160; &#160;V <br />V₁ = &#160; &#160; &#160; &#160;V <br />V₂ = &#160; &#160; &#160; &#160;V <br />I₁ = &#160; &#160; &#160; &#160; mA <br />I₂ = &#160; &#160; &#160; &#160; mA</p>

Explanation / Answer

eff resistance=(5.5||23)+11=15.439 kohm i=v/r=15/15.439*10^3=0.972 mA i through r3=0.972 mA v=ir=0.972*11=10.692 V r2||r1=4.439 kohm current through r2||r1 = 0.972 mA voltage across r2,r1=ir=0.972*4.439=4.314 V current through r2=0.188 mA through r1=0.784 mA

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