With what speed v did the particle enter the region containing the magnetic fiel

Question

With what speed v did the particle enter the region containing the magnetic field? (m/s)

V=(pi * d/2)/t = (3.14 * .415)/776*10^-6 = 1680

2) What is Fx, the x-component of the force on the particle at a time t1 = 258.7 s after it entered the region containing the magnetic field. (N)

A charged particle of mass m = 5.6X10 - 8 kg, moving with constant velocity in the y - direction enters a region containing a constant magnetic field B = 3.5T aligned with the positive z - axis as shown. The particle enters the region at (x,y) = (0.83 m, 0) and leaves the region at (x,y) = 0, 0.83 m a time t = 776 mu s after it entered the region. With what speed v did the particle enter the region containing the magnetic field? (m/s) V=(pi * d/2)/t = (3.14 * .415)/776*10^ - 6 = 1680 2) What is Fx, the x - component of the force on the particle at a time t1 = 258.7 mu s after it entered the region containing the magnetic field. (N)

Explanation / Answer

1) the velocity of the particle is given by v = *d/(2*t) = 1680.10 m/s

2)we find the angle through which the article has rotated by = v*t'/d = /6 = 30 degrees

=> the centifugal acceleration of the particle is a = v^2/d *(cos(30) i + sin(30) j )

=> the x-component of force Fx = m*v^2*cos(30)/d = 0.1649 N

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