A capacitor consists of two charged disks of radius 3.2 m separated by a distanc
ID: 2055561 • Letter: A
Question
A capacitor consists of two charged disks of radius 3.2 m separated by a distance s = 2 mm (see the figure). The magnitude of the charge on each disk is 43 µC. Consider points A, B, C, and D inside the capacitor, as shown in the diagram. The distance s1 = 1.3 mm, and the distance s2 = 0.5 mm. (Assume the +x axis is to the right, the +y axis is up, and the +z axis is out.)(a) What is the electric field inside the capacitor?
E= ?
(b) First, calculate the potential difference VB - VA.
What is Delta l along this path?
Delta l = ? m
What is VB - VA?
VB - VA = ? volts
(c) Next, calculate the potential difference VC - VB.
What is Delta l along this path?
Delta l = ? m
(d) Finally, calculate the potential difference VA - VC.
What is Delta l along this path?
Delta l = ? m
What is VA - VC?
VA - VC = ? volts
Explanation / Answer
a) E = V/d= Q/Cd = Q/(A/d)*d = 43*10^-6/(8.854*10^-12**3.2^2/.002)*.002 = 1.51*10^5 V/m
b) as you hav not provided the diagram, i cannot provide you the solution for the other parts...
but can tell you the method,
take the -ve plate to be at 0 Volts and the +ve palte as V volts
suppose A is at x distance from the -ve plate, so, Va = E*x and repeat this with other points also..
you can fing Va -Vb, Vb-Vc and so on....
hope this helps...
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