FIRST SITUATION: \"An object of mass \'M\' is suspended as shown in the figure b

Question

FIRST SITUATION:

"An object of mass 'M' is suspended as shown in the figure below. A smaller mass 'm' is hanging over an ideal pulley such that it stretched the spring and when the object is in equilibrium the hanging string is perfectly vertical"

Picture here... http://imageshack.us/photo/my-images/215/objectv.png/

SECOND SITUATION:

"An object of mass 'M' is suspended as shown. The entire system rotates around a vertical axis with constant speed such that when the spring is stretched the string is perfectly vertical"

Picture here... http://imageshack.us/photo/my-images/13/object2.png/

Part 1: Find the elastic force in the spring in case A as a function of the mass m

Part 2: Find the elastic force in the spring in case B, considering that the distance from object M to the axis of rotation is R and the system rotates with a constant speed v.

Explanation / Answer

Part 1) F=kx=mg Part 2) centripetal acceleration = (v^2/R) Force=mass*acceleration so F=M(v^2/R) And so these two values will be the same for the same object.

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.