In a Fourth of July celebration, a firecracker is launched from ground level wit

Question

In a Fourth of July celebration, a firecracker is launched from ground level with an initial velocity of 19.6m/s at 32.1o from the vertical. At its maximum height it explodes in a starburst into many fragments, two of which travel forward initially at 15.5 m/s at ±49.8o with respect to the horizontal, both quantities measured relative to the original firecracker just before it exploded.

With what angles with respect to the horizontal do the two fragments initially move right after the explosion, as measured by a spectator standing on the ground?

Explanation / Answer

1 ) Vfragments/cracker = Vf/g - Vc/G Vf/g = Vc/g + Vf/c = 19.6*cos(32.1)i + 19.6*sin(32.1)j + 15.5*cos(49.8)i + 15.5*sin(49.8)j = 26.06i + 22.25j angle = 40.49 2 ) Vfragments/cracker = Vf/g - Vc/G Vf/g = Vc/g + Vf/c = 19.6*cos(32.1)i + 19.6*sin(32.1)j + 15.5*cos(49.8)i - 15.5*sin(49.8)j = 26.06i - 1.42j angle = -3.1189

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