(c) What additional quantity or quantities are needed to calculate the total cur

Question

(c) What additional quantity or quantities are needed to calculate the total current in this ion beam? (Select all that apply.)

BTW I have tried this (4e8)(2)(1.6e-19)(1.2e5) and I have tried this (2*400)(1.6e-19)(1.2e5) neither will work

A beam contains 4.0 108 doubly charged positive ions per cubic centimeter, all of which are moving north with a speed of 1.2 105 m/s. (a) What is the magnitude of the current density J? (c) What additional quantity or quantities are needed to calculate the total current in this ion beam? (Select all that apply.) BTW I have tried this (4e8)(2)(1.6e-19)(1.2e5) and I have tried this (2*400)(1.6e-19)(1.2e5) neither will work

Explanation / Answer

J = nev
n = 4.0 x 10^8 * 2 because the ions are doubly charged.
e = 1.6 * 10^-19
v = 1.2 * 10^5
J = 4.0 x 10^8 * 2*1.6 * 10^-19*1.2 * 10^5 = 15.36 * 10^-6

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.