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Question

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As shown, a pipe is anchored to a wall at point A. (Part B figure) During the pipe's installation, several forces are applied to the pipe at different locations. If F1= 18.5lb , F2 = 12.5lb , F3 = 11.0lb , F4 = 18.2lb, d1 = 0.500ft , d2 = 0.750ft , and d3= 0.700ft , what is M_Ra , the net moment about point A due to these forces? Assume that moments acting counterclockwise about point A are positive whereas moments acting clockwise are negative.

Express your answer numerically in pound-feet to three significant figures.

Explanation / Answer

Moment due to F1 = d2*F1 Moment due to F2 = -d2*F2 Moment due to F3 = 0 Moment due to F4 = - (d3-d1) F4 Net moment = d2*F1 - d2*F2 - (d3-d1) F4 On solving we get Net moment = 13.875 - 9.375 - 3.64 lb-ft = .86 lb-ft

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