A baseball is thrown straight up. The drag force is proportional to v^2. -In ter

Question

A baseball is thrown straight up. The drag force is proportional to v^2.

-In terms of g, what is the y-component of the ball's acceleration when its speed is half its terminal speed and it is moving up?Express your solution with three significant digits, and +y direction is upwards. Omit the unit (m/s2).

-In terms of g, what is the y-component of the ball's acceleration when its speed is half its terminal speed and it is moving back down? Express your solution with three significant digits, and +y direction is upwards. Omit the unit (m/s2).

Explanation / Answer

let teh drag force = kv^2 k is proportionality constant at terminal speed mg = kv^2 terminal speed V= sqrt(mg/k) half terminal speed = .5sqrt(mg/k) a) while moving up mg and kv^2 are in same direction (downwards) ma = mg+kv^2 ma = mg + k(mg/4k) ma = 5mg/4 a = 5g/4 = 1.250g downwards the y-component of the ball's acceleration when its speed is half its terminal speed and it is moving up = -1.250*g b) wile moving down mg and kv^2 are in opposite direction ma = mg -kv^2 ma = mg - mg/4 = 3mg/4 a = 3g/4 = 0.750g downwards what is the y-component of the ball's acceleration when its speed is half its terminal speed and it is moving back down is -0.750*g I hope this is clear to you

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.