A man pushes a 2.0 kg broom at constant speed across the floor. The broom handle

Question

A man pushes a 2.0 kg broom at constant speed across the floor. The broom handle makes a 50 degree angle with the floor. He pushes the broom with a 5.0 N force.

a.) Sum of the forces in the y-direction. What is the value of the normal force?

b.) Sum of the forces in the x-direction. What is the value of the frictional force opposing the motion?

c.) If the frictional force were suddenly reduced to zero, what would happen to the broom?

Explanation / Answer

(a)the value of the normal force N +5*sin50=mg => N=15.77N (b)the value of the frictional force F opposing themotion constant speed across the floor =>acceleration =0 => 5*cos50 -F=0 => F=3.21 N (c)If the frictional force were suddenly reduced byzero, the broom is under a acceleration of a a=5*cos50/2=1.6m/s2

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