The world\'s fastest land animal, the cheetah, can accelerate at 5 m/s2 to a top
ID: 2046702 • Letter: T
Question
The world's fastest land animal, the cheetah, can accelerate at 5 m/s2 to a top speed of 25 m/s. A cheetah observes a passing gazelle traveling at Vg = 6 m/s and begins chase.Assume that d1 is the distance the cheetah is away from the gazelle when it reaches full speed. Derive an expression in terms of the variables d1, vc and vg for the time ,tc, it takes the cheetah to catch the gazelle.
ok i got four equations that relate velocities distance, and time but i dunno how to relate two separate velocities except starting and initial of the same particle im stuck
Explanation / Answer
Time taken to reach full speed Vc = a*t t= Vc/a distance = d1 relative speed = Vc- Vg so, time taken to catch the gazzelle = d1 / (Vc- Vg) So, total time = d1 / (Vc- Vg) + Vc/a I hope this answers you
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