A pendulum consists of a 4.0-kg ball fastened to the end of a 3.0-meter-long len

Question

A pendulum consists of a 4.0-kg ball fastened to the end of a 3.0-meter-long length of strong wire. We set it oscillating back and forth with an amplitude ? = 0.120 radians.
(A) What is the period of oscillation?
(B) What is the maximum speed of the ball?
(C) What is the total energy of the system? (Note: we assume that gravitational PE is zero at the bottom of the swing.) J.

I found the period of oscillation to be 3.5 seconds. I do not know how to find the maximum speed of the ball. I tried vmax = omega * amplitude and that did not work. Can anyone help me?

Explanation / Answer

max speed is omega*angular amplitude * L = sqrt(g/L) * 0.12*L =sqrt(gL)*0.12=sqrt(9.81*3)*0.12=0.65 m/s total energy = 0.5 * m v^2=0.5 *4 * 0.65^2=0.845 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.