Your cat bounds from his original position 5.00m northward in 3.00s to dig up a

Question

Your cat bounds from his original position 5.00m northward in 3.00s to dig up a toy, which takes 18.00s; he then takes the toy in his mouth and goies another 4.00m westward in 4.00s; finally, he sees you, turns immediately, and goes 36.9 degrees east of south 3.00m, taking 5.00s. He puts the toy downat your feet.
Determine the net distance traveled by the cat;his net displacement; his average speed and average velocity for the entire trip.
Hint: use north and west to specify the axes of your coordinate system.

Explanation / Answer

total distance = 5 + 4 + 3 = 12 m Total time = 3+18+4+5 = 30 seconds Average speed = 12/30 = 0.4 m/s

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