Elevator cabs A and B are connected by a short cable and can be pulled upward or

Question

Elevator cabs A and B are connected by a short cable and can be pulled upward or lowered by the cable above cab A. Cab A has mass mA; cab B has mass mB. A box with mass mc lies on the floor of cab A. The tension in the cable connecting the cabs is T. Note masses are in kg, tension is in Newton and g is in m/s2. What is the magnitude of the normal force on the catnip box from the floor of cab A? Your final answer should be only in terms of T,mc and mB. Express the answer in terms of these variables and do not worry about units. Assume T/mB >g.

Explanation / Answer

T-mBg=mBa T = mB(a+g) a+g=T/mB I found that a+g=T/mB So, I replaced a+g by T/mB

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