Two charges, -20 C and +4.2 C, are fixed in place and separated by 2.4 m. (a) At

Question

Two charges, -20 C and +4.2 C, are fixed in place and separated by 2.4 m. (a) At what spot along a line through the charges is the net electric field zero? Give the distance of the spot to the positive charge in meters (m). (Hint: The spot does not necessarily lie between the two charges.) (b) What would be the force on a charge of +14 C placed at this spot?

Explanation / Answer

let the distance be x m from 4.2 C away from -20 => 4.2 / x^2 = 20 / (x+2.4)^2 => (x+2.4)/x = 2.18 so 2.4 = 1.18x =>x = 2.03 m from +4 C away from -20 C b) now since the resultant field at that point is 0 F = Eq = 0

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