a : HbS allele frequency: 0.18 HbA allele frequency: 0.82 b . Yes 1-0.18 = 0.82
ID: 204295 • Letter: A
Question
a: HbS allele frequency: 0.18 HbA allele frequency: 0.82
b. Yes 1-0.18 = 0.82
c. HbA/HbA
HbS/HbA
HbS/HbS
d. HbS/HbS genotype frequency: (0.18)2 = 0.0324
HbA/HbA genotype frequency: (0.82)2 = 0.6724
HbS/HbA genotype frequency: 2 (0.18) (0.82) = 0.2952
e. 0.0324 x 1000 = 32.4 (33 people)
f. ????
g. ????
Can someone please check my answers and help with question f and g?
21. In the human populations in Angola, Africa, the hemoglobin allele has two alleles: HbS and HbA. (a) The HbS allele has a frequency of 0.18. What is the frequency of HbA? (b) Did you need to use the Hardy-Weinberg equations to calculate the previous answer? Yes OR no? (c) What are the possible genotypes? (d) Assuming Hardy-Weinberg, what are these genotype frequencies? (e) People who are homozygous for the HbS allele have sickle-cell anemia, a disease that can block blood flow and often leads to early death. If you tested 1000 people in Angola, how many would you predict to have sickle-cell anemia? (1) The actual number is typically much much lower than the prediction. Why do you think that is? (g) Do you think the hemoglobin gene is in Hardy-Weinberg equilibrium? Why or why not?Explanation / Answer
G. HWE has a assumption following assumption
1. No mutations must occur so that new alleles do not enter the population.
2. No gene flow can occur (i.e. no migration of individuals into, or out of, the population).
3. Random mating must occur (i.e. individuals must pair by chance)
4. The population must be large so that no genetic drift (random chance) can cause the allele frequencies to change.
5. No selection can occur so that certain alleles are not selected for, or against.
This assumption not able to follow in real situation or environment. So, the observed value is change compare to expected value.
G. Yes it is a hardy weinberg equillibrium. The Hardy-Weinberg formulas allow us to detect some allele frequencies that change from generation to generation, thus allowing a simplified method of determining that evolution is occurring.
It follows the two conditions,
p2 + 2pq + q2 = 1
and
p + q = 1
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