I am almost finished with my homework, but for some reason I can\'t get these tw
ID: 2042528 • Letter: I
Question
I am almost finished with my homework, but for some reason I can't get these two questions right.A car battery has a rating of 190 ampere-hours. This rating is one indication of the total charge that the battery can provide to a circuit before failing. (a) What is the total charge (in coulombs) that this battery can provide? (b) Determine the maximum current that the battery can provide for 55 minutes.
An electric furnace runs 7.9 hours a day to heat a house during January (31 days). The heating element has a resistance of 7.2 and carries a current of 16.7 A. The cost of electricity is $0.10/kWh. Find the cost of running the furnace during January.
Explanation / Answer
190 amp* hour = 190 * 60*60 amp.second. = 684000 amp, second. Ampere = coloumb /s. Hence 190 amp.hour = 684000 coloumb.second / second = 684000 C. Thus this rating is one indication of the total charge. ========================== a.) What is the total charge in coulombs that this battery can provide? The answer is 684000 C. =========================== b.) To find the maximum current we divide the amp hour by time to eliminate the time. 190 amp * 60 minutes / 55 minutes = 207.27 amp/ or from Charge /time = current = 684000 C / (55*60) s = 207.27 C/s = 207.27 amp. ===========================
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