1 pt| Light with a wavelength of ? = 560 nm is incident on a diffraction grating
ID: 2041379 • Letter: 1
Question
1 pt| Light with a wavelength of ? = 560 nm is incident on a diffraction grating. A screen is placed at a distance of L 2.85 m from the grating. The grating has 140 lines per millimeter. What is the distance between the m- 3 maximum and the central (i.e. zeroth order) maximum on the screen? Important note: You should not use the small angle approximation. (in m) 30. AO 3.53 × 10-1 BO 4.41 × 10-1 co 5.52 × 10-1 DO 6.90 x 10-1 GO 1.35 10-1 FO 1.08 O 8.62 × HO 1.68 E 30) . 6.90E-01 [0.675873894109647 0.703460583665143] Sig 3 -5 Unit: mExplanation / Answer
condition for diffraction
d sin theta = m lamda
for small angles sin theta = tan theta = y/L
d ( y/L) = m lamda
d = 1/N = 1/140/mm
= mm/140
= 10^-3 m/140
= 7.14 * 10^-6 m
d ( y3/L) = 3 lamda
y3 = 3 * lamda *l/ d
= 3 ( 560* 10^-9)(2.85)/7.14 * 10^-6 m
= 0.690 m
= 6.9 * 10^-1
option(D) is correct answer
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