(1) (3 points) A flat circular ring of wire with radius 56.5 cm lies horizontall

Question

(1) (3 points) A flat circular ring of wire with radius 56.5 cm lies horizontally in a uniform magnetic field with field strength of 4.00 T. The uniform field is rotated to various directions, as shown in the diagrams below. (b) The field makes a 30° angle with the horizontal surface. (c) The field is parallel to the horizontal surface (a) The field is perpendicular to the horizontal surface. Calculate the magnetic flux through the circular ring in case (a), case (b), and case (c). Make sure to write the numerie values using the correct SI units.

Explanation / Answer

magnetic flux (phiB) = N A B sin theta

partA :

magnetic flux (phiB) = 1 * 3.14 * 0.565* 0.565 * 4 * sin 90

phiB = 4 Wb

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part B :

magnetic flux (phiB) = N A B sin theta

magnetic flux (phiB) = 1 * 3.14 * 0.565* 0.565 * 4 * sin 30

phiB = 2 Wb

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part c :

magnetic flux (phiB) = N A B sin theta

magnetic flux (phiB) = 1 * 3.14 * 0.565* 0.565 * 4 * sin 0

phiB = 0 Wb

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