ado n a generator, an outside source of mechanical motion supplies the energy to
ID: 2041341 • Letter: A
Question
ado n a generator, an outside source of mechanical motion supplies the energy to move a magnet in a magnetic field. A generator works just like the moving magnet in a magnetic field (as in Part II) . Click on Show Field and observe the moving magnetic field Changing Changing Summary: Lenz's Law states that the induced EMF opposes the change in the magnetic field. Imagine you were actually turning the water wheel by hand to generate current Would the wheel resist motion? As you worked harder at moving the wheel, you would expect?e light to shine Explain what is happening in the saimulation's generator and in Hoover Dam in terms of the law of conservation of energy Changing Changing Results Results Results Results = ML48 You investigated each of the variables that has Faraday's Law can be summarized with the formula: e an effect on emf (electromotive force, like potential or List what each variable is and how it affects emf emf potential to drive electrons in a current Finally, transformers use the ratio of the number of loops in the primary (input) coil to the loops in secondary (ouput) coil to determine the step, or what will happen to the voltage (emf in the system. A transformer with 500 loops in the primary and 1000 loops in the secondary is a 2:1 step-up transformer that will double the imput voltage. Is this free energy or does something have to stepped down? Conclusion Calculations and 1. If the number of loops in a coil around a moving magnet doubles, the emf created doubles/halves/remains the same. 2. If area of a coil around a moving magnet doubles, the emf created dowbles /halves /remains the same 3. If the speed of a moving magnet through a coil doubles, the emf created doubles /halves /remains the same 4. When the polarity of a moving magnet in a coil is flipped, the emf increases/decreases/remains the same. . As current increases in an electromagnet's coil, the strength of the created magnetic field increases/decreases/ remains the same. 6. A DC electromagnet creates a changing/ constant magnetic field and an electromagnet powered with AC creates a changing/consant magnetic field 7. In a step up transformer, the emf(voltage) is stepped up and the 8. The power output of a step up transformer is greater than/less than/ the same as the input power of the transformer 9. 9.0 volts are sent into a transformer with a 10-coil primary loops and a 30-coil secondary loop. The voltage leaving the is stepped down. secondary loop will be 10. The power output of a transformer is 100. W. The input voltage is 25V. What is the coil-turn ratio of the transformer if the output current is 1.0A?Explanation / Answer
Maximum emf = NABw;
where, N = number of turns;
A = circuit area (m2);
B = magnetic field strength (T);
w = angular frequency of rotation.
1) If the number of loops in a coil around a moving magnet doubles, the emf created doubles.
as emf = NABw. (N = number of loops).
2) If area of a coil around a moving magnet doubles, the emf created doubles.
3) If the speed of a moving magnet through a coil doubles, the emf created doubles.
4) When the polarity of a moving magnet in a coil is flipped, the emf remains the same.
5) As current increases in an electromagnet’s coil, the strength of the created magnetic field increases. (as emf is increasing so current will increase.)
6) A DC electromagnet creates a constant magnetic field and an electromagnet powered with AC creates a changing magnetic field.
7) In a step up transformer, the emf (voltage) is stepped up and the current is stepped down. (as for the same power P = V1I1 = V2I2)
8) The power output of a step up transformer is the same as the input power of the transformer.
9) 9.0 volts are sent into a transformer with a 10-coil primary loops and a 30-coil secondary loop. The voltage leaving the secondary loop will be 27V. (as V1N2 = V2N1)
10) The power output of a transformer is 100. W. The input voltage is 25V. What is the coil-turn ratio of the transformer if the output current is 1.0 A is 1:4 stepup (as P = 100 = V1I1, so I1 = 1/4 therefore N2/N1 = V2/V1 =I1/I2 = 1/4).
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