A car initially traveling with a velocity if 12 m/s accelerates at a constant ra

Question

A car initially traveling with a velocity if 12 m/s accelerates at a constant rate of 2.5 m/s^2 for 2 seconds. A) will this car cover more or less ground in 2 seconds than a second car initially moving at 12m/s but no acceleration ?
B) how far is this car moving after 2seconds ?
C) how far has it traveled during the 2 second interval ? A car initially traveling with a velocity if 12 m/s accelerates at a constant rate of 2.5 m/s^2 for 2 seconds. A) will this car cover more or less ground in 2 seconds than a second car initially moving at 12m/s but no acceleration ?
B) how far is this car moving after 2seconds ?
C) how far has it traveled during the 2 second interval ? A) will this car cover more or less ground in 2 seconds than a second car initially moving at 12m/s but no acceleration ?
B) how far is this car moving after 2seconds ?
C) how far has it traveled during the 2 second interval ?

Explanation / Answer

A) since the car is travelling with accleration at a constant rate. it will cover more ground than the second car which is moving without accleration.

B) we have from the kinematics,

v = u + a*t

where,

u = initial velocity = 12 m/s

a = accleration = 2.5 m/s2

t = time = 2 seconds

thus

v = 12 m/s + (2.5)(2) = 17 m/s

C) the distance can be calculated from the formula

s = u*t + at2/2
s = (12*2) + 0.5*(2.5)(2)2 = 29 m
s = 22.5 m / 2 + 42 m
s = 11.25m + 42m
s = 53.25 m

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