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please answer 9-11 as an internal resistance of 0.5 O ond is attached to s o ius

ID: 2040287 • Letter: P

Question

please answer 9-11

as an internal resistance of 0.5 O ond is attached to s o ius" what happe. to the current through the circait if the load is increased? A) The current will not change B) Current will increase D? E) current will decrease The current wil, increase and decrease in, snus odal hncion Not enough information sgiven 10. What is the resistance of a 100 W lightbulh if it draws a 04 amp urrent? 8) 10? C)2500 DI 625 ? E) 10000 11. A kitchen contains a 900 W toaster, a 720 W microwave, and a 350 W miser The outlets are 120-V and are connected in parallel (which allows you to add up the current to find a totall, the circuit breaker is tripped if the current goes over 15 A which combination of appliances when used simultaneously, will trip the circuit breaker? A) Toaster and microwave Bl Toaster and mixer C) Mixer and microwave D) Toaster, mixer, and microwave E) All of the above

Explanation / Answer

9) option C is the answer

V=E-Ir

where V is the voltage drop across the load ,E is the emf of the cell,r is the internal resistance of the celI and I is the current flowing through the circuit.

when the load is increased the voltage drop across the load increases and current decrease.

10) option D

P=I2r

Resistance r=P/I2

=100/0.16=625 ohms

11)Option D is answer.

When the appliances are connected in parallel to the power supply ,the voltage drop in each appliance is same.In the combination if the current exceeds 15A ,will trips the circuit breaker.Therfore the current across each appliance can be calculated using the equation P=VI,where P is the power ,V voltage I ,is the current produced.

Current produced in toaster is7.5A, microwave=6A,mixer=2.91A

so the combination of the above three results in 16.41A which exceeds the limit.thus circuit breaks