HW12-Linear Momentum Item 24 24 of 26> What is the speed before of the girl imme
ID: 2040213 • Letter: H
Question
HW12-Linear Momentum Item 24 24 of 26> What is the speed before of the girl immediately before she grabs the box? Express your answer numerically in meters per second. A girl of mass m1 60.0 kilograms springs from a trampoline with an initial upward velocity of vi 8.00 meters per second. At height h 2.00 meters above the trampoline, the girl grabs a box of mass m2 = 15.0 kilograms. (Figure 1) View Available Hints) For this problem, use g 9.80 meters per second per second for the magnitude of the acceleration due to gravity before m s Submit Part B What is the speed after of the girl immediately after she grabs the box? Express your answer numerically in meters per second. View Available Hint(s) Figure 1 of 1 Vafter Submit m12 Part C This question will be shown after you complete previous question(s). ? Part D What is the maximum height hmax that the girl (with box) reaches? Measure hgnax with respect to the top of the trampoline. Express your answer numerically in meters. View Available Hint(sExplanation / Answer
A)
As the girl goes up her speed decreases.
using one of the equations of motion,
v_before^2 - vi^2 = 2*(-g)*h
v_before^2 = vi^2 - 2*g*h
v_before = sqrt(vi^2 - 2*g*h)
= sqrt(8^2 - 2*9.8*2)
= 4.98 m/s
B) using conservation of momentum
v_after*(m1 + m2) = m1*v_before
v_after = m1*v_before/(m1+m2)
= 60*4.98/(60 + 15)
= 3.98 m/s
D) Hmax = h + v_after^2/(2*g)
= 2 + 3.98^2/(2*9.8)
= 2.81 m
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