25%) Problem 1: A bare helium nucleus consists of two protons and two neutrons a

Question

25%) Problem 1: A bare helium nucleus consists of two protons and two neutrons and has a mass of 6.64 × 10-27 kg 25% Part (a) Calculate its kinetic energy in joules at 1.5 % of the speed of light. Use the non-relativistic formula K-6.7* 10 13 Grade Summary Deductions 5% 95% Submissions sinO tan() | ? cosO cotanOasin) acosO 78 9HOME 41516 ? Attempts remaining: 9 % per attempt) detailed view atan0a acotan)sin h0 5% cosh0tan0 cotanho Degrees O Radians 0 ENID VOI BACKSPACE | DEL| CLEAR Submit Feedback I give up! ints: 0 for a 0% deduction. Hint s remaining:0 Feedback: 3% deduction per feedback ? 25% Part (b) What is this in electron volts? 25% Part (c) Enter an expression for the voltage needed to obtain this energy, in terms of the kinetic energy, K, and the charge, q, of the ucleus -là 25% Part (d) Calculate the voltage, in volts, needed to obtain this energy

Explanation / Answer

a) 1.5% velocity of kight = [1.5 / 100] * 3 * 108 = 4.5 * 106 m/s

KE = 1/2 m v2 = 1/2 * 6.64 * 10-27 * (4.5 * 106)2

kinetic energy = 6.72 * 10-14 J

b) KE = 6.72 * 10-14 / 1.6 * 10-19

= 4.20 * 105 eV

c) expression for voltage = K / q

d) voltage = (6.72 * 10-14) / (1.6 * 10-19)

= 4.20 * 105 V

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