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I need help to solve question thank you The secret-secret spy satellite \"Peek-a

ID: 2039881 • Letter: I

Question

I need help to solve question thank you

The secret-secret spy satellite "Peek-a-Boo 5 1/2" orbits the Earth at an altitude of 31,000 km above the surface of the Earth. The orbit is circular and the satellite has a mass of 3500 kg a) What is the satellite's orbital speed? b) What is the satellite's orbital period? SHOW ALL YOUR WORK!! REam 6380 km, Mth 5.98 x 104 xg T1-84 Plus TEXAS INSTRUMENTS SEAT PLOT FI TBLSET F2 QUIT MODE DEL ALOCK TEST A ANGLE DRAWST CLEAR MATH APPS PRG MATRIX D SN E SIN COS TAN 789 6 LN 4 L1 Y 2

Explanation / Answer

Using force balance on satellite

Fg = Fc

G*M*m/r^2 = m*V^2/r

V = sqrt (G*M/r)

Time period is given by

T = 2*pi/w = 2*pi*r/v

T = 2*pi*sqrt (r^3/GM)

Part A

r = orbital speed = H + Re = 31000 km + 6371 km = 3.737*10^7 m

M = mass of earth = 5.98*10^24 kg

V = sqrt (6.67*10^-11*5.98*10^24/(3.737*10^7))

V = 3267 m/sec

Part B

T = 2*pi*sqrt ((3.737*10^7)^3/(6.67*10^-11*5.98*10^24))

T = 71870.56 sec = 19.96 hr

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