I need help to solve question thank you The secret-secret spy satellite \"Peek-a
ID: 2039881 • Letter: I
Question
I need help to solve question thank you
The secret-secret spy satellite "Peek-a-Boo 5 1/2" orbits the Earth at an altitude of 31,000 km above the surface of the Earth. The orbit is circular and the satellite has a mass of 3500 kg a) What is the satellite's orbital speed? b) What is the satellite's orbital period? SHOW ALL YOUR WORK!! REam 6380 km, Mth 5.98 x 104 xg T1-84 Plus TEXAS INSTRUMENTS SEAT PLOT FI TBLSET F2 QUIT MODE DEL ALOCK TEST A ANGLE DRAWST CLEAR MATH APPS PRG MATRIX D SN E SIN COS TAN 789 6 LN 4 L1 Y 2Explanation / Answer
Using force balance on satellite
Fg = Fc
G*M*m/r^2 = m*V^2/r
V = sqrt (G*M/r)
Time period is given by
T = 2*pi/w = 2*pi*r/v
T = 2*pi*sqrt (r^3/GM)
Part A
r = orbital speed = H + Re = 31000 km + 6371 km = 3.737*10^7 m
M = mass of earth = 5.98*10^24 kg
V = sqrt (6.67*10^-11*5.98*10^24/(3.737*10^7))
V = 3267 m/sec
Part B
T = 2*pi*sqrt ((3.737*10^7)^3/(6.67*10^-11*5.98*10^24))
T = 71870.56 sec = 19.96 hr
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