1. (20 points) A particle of mass m 1.609 x 10-10 kg and charge 1.609 x 10-19 C
ID: 2039867 • Letter: 1
Question
1. (20 points) A particle of mass m 1.609 x 10-10 kg and charge 1.609 x 10-19 C is moving at u = 1.00 x103 m/s in the -z-direction as it enters a region of space containing a rnagnetic field B = 0.500 T, which is constant and directed at an angle of 45.0° with respect to the +z-axis. (a) What is the magnitude of the acceleration of the particle? (b) What is the direction of this acceleration? 2. (20 points) A circular wire loop of resistance R is initially in a region where there is no magnetic field. The loop is then moved into a region where there is a constant magnetic field B, pointing into the page, as shown in Figure 1. This process takes 2.0 ms. (a) What is the magnitude of the current induced in the loop? (b) In which direction does the current flow in the loop? (c) Suppose that the loop is kept in the region with the magnetic field, but the magnetic field varies according to B = 12.0-8.0t. Answer parts (a) and (b) for this circumstance. 1.5T Figure 1: This is the figure for Problem 2Explanation / Answer
1) m = 1.609*10^-10 kg, q = 1.609*10^-19 C, v = 1*!0^3 ms, B = 0.5 T , theta = 45 degress
(a) F = qvBsin(theta)
F = ma
1.609*10^-10*a = 1.609*10^-19*1*10^3*0.5*sin(45)
a = 3.54 m/s^2
(b) from right hand thumb rule acceleration is along into the page
F = q(vxB) = (-ix j)= -k
(c) from data, they didnot mentioned Resistance value R
t = 2ms, r = 12cm
(a) from faradays law
induced emf V = -d(phi)/dt
V= A(B1-B2)/t
V = 3.14*0.12^2*(1.5-0)/0.002
V = 33.912 V
I = V/R
I = 33.912/R
(b) from Lenz law current is along counter clock wise direction
(c) V = A(dB/dt)
B = 12-8t
dB/dt = -8
V = 3.14*0.12^2*8
V = 0.36173 V
I = 0.36173/R
current is along countet clock wise direction
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.