A 1.3 kg handgun initially holds a 16 g bullet out rest. The bullet is fired to
ID: 2039575 • Letter: A
Question
A 1.3 kg handgun initially holds a 16 g bullet out rest. The bullet is fired to the right with the final muzzle speed of 330 m/s. Assume that nobody is holding the gun either it is floating in space or else it fires the bullet horizontally while sitting on a frictionless horizontal surface on earth. Assume also that the bullet is ejected away from the center of mass of the gun so that the gun deals no net torque and does not start to rotate. What is the guns recoil speed to the left? DONT ANSWER ALREADY ANSWERED 4.01 M/S JUST ANSWER PART B: What is the total change in Connecticut energy of the system? Is it elastic or inelastic?
Explanation / Answer
A)
let M = 1.3 kg
m = 16 g = 0.016 kg
v = 330 m/s
let v' is the recoil speed of gun
Apply conservation of momentm
M*v' = m*v
v' = m*v/M
= 0.016*330/1.3
= 4.06 m/s
B) change in kinetic energy = kinetic energy after bullet leaves the gun - kinetic energy before bullet leaves the gun
= (1/2)*m*v^2 + (1/2)*M*v'^2 - 0
= (1/2)*0.016*330^2 + (1/2)*1.3*4.06^2 - 0
= 882 J
It is inelastic.
because, kinetic enrgy is not conserved.
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