Problem 30.51 A small, 2.00-mm-diameter circular loop with R = 1.20×10?2 ? is at

Question

Problem 30.51 A small, 2.00-mm-diameter circular loop with R = 1.20×10?2 ? is at the center of a large 120-mm-diameter circular loop. Both loops lie in the same plane. The current in the outer loop changes from +1.0A to ?1.0A in 8.00×10?2 s . Part A What is the induced current in the inner loop?

Problem 30.51 A small, 2.00-mm-diameter circular loop with R 1.20x10-2 ? is at the center of a large 120-mm-diameter circular loop. Both loops lie in the same plane. The current in the outer loop changes from +1.0 A to -1.0 A in 8.00x102 Part A What is the induced current in the inner loop? Express your answer with the appropriate units. 59 nA SubmitPrev Previous Answers Request Answer

Explanation / Answer

r = 2 mm / 2 = 1.0 mm

r1 = 120 / 2 = 60 mm

I = E / R = -d(pi r2) B / R dt

I = pi r2 [mu0 / 2 r1 R] di/dt

= (pi * (1 * 10-3)2 * 4 pi * 10-7) / (2 * 60 * 10-3 * 1.2 * 10-2) * (-1 - 1 / 0.08)

= 6.85 * 10-8 A = 68.5 nA

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