at what speed would a 2.07x10^4 kg airplane e a momentum of 1.91 x 10 kg m/s (si

Question

at what speed would a 2.07x10^4 kg airplane e a momentum of 1.91 x 10 kg m/s (similar to the momentum of a large moving ship)? m/s (b) What is the plane's momentum (in kg m/s) when it is taking off at a speed of 55.8 m/s? kg m/s of your answer to (b) as it relates to recoil effects of the catapult (c) If the shjp is an aircraft carrier that launches these airplanes with a catapuit, discuss the implications on the shlp Since the momentum of the airplane is much smaller than that of the ship, the ship will not experience a significant recoll effect from the catapult. Since the momentum of the airplane is Since the momentum of the airplane is much larger than that of the ship, the ship wil experience a significant recoll effect from the catapult. Since the momentum of the airplane is much smaller than that of the ship, the ship will experience a significant recoil effect from the catapult much larger than that of the ship, the ship will not experience a significant recoll effect from the catapult

Explanation / Answer

Part A

Momentum is given by:

P = m*V

V = P/m = 1.91*10^9/(2.07*10^4)

V = 92270.53 m/sec

Part B

P = m*V

P = 2.07*10^4*55.8

P = 1155060 kg-m/sec

Part C

Since mass of airplane <<<< mass of ship, So ship will not experience a significant recoil

Usin momentum conservation

Pi = Pf

Pi = 0, when both ship and airplane were at rest,

So, Pf = 0

Mp*Vp - Ms*Vs = 0

Vs = Mp*Vp/Ms

Mp <<<< Ms

Mp/Ms <<<< 1

Vs = 55.8*(very low quantity) = not significant recoil

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