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17. An emf of 0.52 V is induced in a 0.62-H inductor. What is the rate of change

ID: 2039243 • Letter: 1

Question

17. An emf of 0.52 V is induced in a 0.62-H inductor. What is the rate of change of current through the inductor? a. 0.84 A/s b. 1.2A/s c. 0.32 A/s d. 1.14 A/s e. 0.62 A/s 18. Solenoid No. 1 has a length L, cross-sectional area A, and N turns. Solenoid No. 2 has a length 2L, cross-sectional area 2A, and 2N turns. Which solenoid has the greater magnetic feld at its center when equal currents are going through them? a No. 1 b. No. 2 c. Both have the same magnetic field. d. Since it depends on the values of A and L, none of the above are correct. 19. What is the impedance of an AC series cireuit that is constructed of a 12.80-12 resistor along with 11.470 inductive reactance and 721 ? capacitive reactance? a. 31.5? b.17.1? e, 15.6 ? d. 13.5 ? 20. The magnetic field going through a stationary circular loop increases from zero to 5T in a certain time t. The induced current in the loop will depend on the radius of the loop, r, the resistance of the loop, R, and the time, t. If two of these stay constant, the induced current can be directly proportional to: b. r c. R d. none of these 21. A square coll, enclosing an area with sides 3.0 cm long, is wrapped with 2500 turns of wire. A uniform magnetic feld perpendicular to its plane is turned on and increases to 0.15T during an interval of 1.9s What average voltage is induced in the coil? a 0.18 V b. 034 V d. 0.06 V e. 0.9V

Explanation / Answer


17) V = 0.52 V, L = 0.62 H
V = L*di/dt
0.52 = 0.62*di/dt
di/dt = 0.84 A/s
correct option is (A)

18) B1= uo*NI/L
B2 = uo*2N*I/2L = B1
correct option is (c)

19) Z = (R^2+(XC -XL)^2)^0.5
Z = (12.8^2 +(7.21 - 11.47)^2)^0.5
Z = 13.5 ohms
correct option is (d)

20) V = IR = N*pi*r^2*(B2-B1)/t
correct option is (d)

21) V = N*L^2*(B2-B1)/t
V = 2500*0.03*0.03*0.15/1.9
V = 0.18 V
correct option is (A)

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