(33%) Problem 1: Two blocks, which can be modeled as point masses, are connected
ID: 2038995 • Letter: #
Question
(33%) Problem 1: Two blocks, which can be modeled as point masses, are connected by a massless string which passes through a hole in a frictionless table. A tube extends out of the hole in the table so that the portion of the string between the hole and M1 remains parallel to the top of the table. The blocks have masses M1 1.3 kg and M2-2.7 kg. Block 1 is a distance r 0.35 m from the center of the frictionless surface. Block 2 hangs vertically underneath. 50% Part (a) Assume that block two, M2, does not move relative to the table and that block one, MI, is rotating the speed of block one, M1, in meters per second? VE sind) | cos() | tan() | ?| (1-)-17 | 8| 9| cotan asinacos0 atan0 acotan sinh0 coshO tanhcotanh0 ODegrees Radians Submit I give up! Hints: 2 for a 6% deduction. Hints remaining: Feedback: 0% deduction per feedback. - Start with a free body diagram for each block, which are connected by the tension in the string. Block M1 experiences centripetal acceleration. 50% Part (b) How much time, in seconds, does it take for block one, M1, to make one revolution?Explanation / Answer
block 2 is in equilibrium
In equilibrium Fnet = 0
T - m2*g = 0
tension T = m2*g
for block 1
net force = m*a
T = m1*v^2/r
m2*g = m1*v^2/r
speed v = sqrt((m2/m1)*g*r)
speed v = sqrt((2.7/1.3)*9.8*0.35) = 2.67 m/s <<----------ANSWER
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time one revolution T = distance/speed 2*pi*r/v = 2*pi*0.35/2.67 = 0.824 s <<----------ANSWER
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